![]() But I do not know how to make such a guess, given one solution. Asking for help, clarification, or responding to other answers. /usr/bin/env python3 Author: Erik Davino Vincent Almost pure Newton-Raphson method implementation for a neural network import numpy as np import matplotlib.pyplot as plt Fits for X and Y def model (X, Y, layerSizes, learningRate, maxiter 100, plotN 100): nx, m X.shape ny Y.shape 0 if m Y. Is there a better way to remove this problem, without using complex functions?Īnother question I have is, can I include the provision of providing more than one root with minor changes to the code? One idea is to change the guess in such a way that now successive iterations bring about another root. Thanks for contributing an answer to Stack Overflow Please be sure to answer the question.Provide details and share your research But avoid. To overcome this, I used g=g+0.001, if the current value of g gives a zero derivative, where g is the current guess. One of the shortcoming of the Newton's method is that or f'(x)=0, it gives a math error and crashes. Print("iterations: ",count,"current guess: ",g) Here is the code I devised:- def deg3(a,b,c,d,g):Į=float(input("e= ")) #for ax^3+bx^2+cx+d=0, with maximum error of e ![]() I started learning python a week ago, and having learnt the basics of using the Newton-Raphson method to solve equations, I came up with a piece of code that can give you atleat (only) 1 solution of a cubic equation. The Newton Raphson method is a widely used algorithm for calculating the implied volatility of an option. ![]() I am completely a beginner in programming, therefore please tell me if the answer to my question is very evident and obvious.
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